Base | Representation |
---|---|
bin | 1010001001011011001001… |
… | …10000010111101010000011 |
3 | 2221000012110012022220212122 |
4 | 11010231210300113222003 |
5 | 10411043131122113011 |
6 | 115242533032114455 |
7 | 4462064564202053 |
oct | 504554460275203 |
9 | 87005405286778 |
10 | 22314045504131 |
11 | 7123373a63277 |
12 | 2604740835a2b |
13 | c5b2895287a4 |
14 | 5720113ad563 |
15 | 28a68d6433db |
hex | 144b64c17a83 |
22314045504131 has 2 divisors, whose sum is σ = 22314045504132. Its totient is φ = 22314045504130.
The previous prime is 22314045504103. The next prime is 22314045504143. The reversal of 22314045504131 is 13140554041322.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-22314045504131 is a prime.
It is a super-3 number, since 3×223140455041313 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 22314045504091 and 22314045504100.
It is not a weakly prime, because it can be changed into another prime (22314045504181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11157022752065 + 11157022752066.
It is an arithmetic number, because the mean of its divisors is an integer number (11157022752066).
Almost surely, 222314045504131 is an apocalyptic number.
22314045504131 is a deficient number, since it is larger than the sum of its proper divisors (1).
22314045504131 is an equidigital number, since it uses as much as digits as its factorization.
22314045504131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 22314045504131 its reverse (13140554041322), we get a palindrome (35454599545453).
The spelling of 22314045504131 in words is "twenty-two trillion, three hundred fourteen billion, forty-five million, five hundred four thousand, one hundred thirty-one".
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