Base | Representation |
---|---|
bin | 1010001001100100100111… |
… | …01100110010110010101011 |
3 | 2221000200120102001200010011 |
4 | 11010302103230302302223 |
5 | 10411134033241010042 |
6 | 115245133233032351 |
7 | 4462334541221266 |
oct | 504622354626253 |
9 | 87020512050104 |
10 | 22319128063147 |
11 | 7125541a2a073 |
12 | 260571a9b56b7 |
13 | c5b8b9502466 |
14 | 572374401cdd |
15 | 28a889956a17 |
hex | 144c93b32cab |
22319128063147 has 2 divisors, whose sum is σ = 22319128063148. Its totient is φ = 22319128063146.
The previous prime is 22319128063087. The next prime is 22319128063181. The reversal of 22319128063147 is 74136082191322.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-22319128063147 is a prime.
It is a super-3 number, since 3×223191280631473 (a number of 41 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 22319128063147.
It is not a weakly prime, because it can be changed into another prime (22319128063447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11159564031573 + 11159564031574.
It is an arithmetic number, because the mean of its divisors is an integer number (11159564031574).
Almost surely, 222319128063147 is an apocalyptic number.
22319128063147 is a deficient number, since it is larger than the sum of its proper divisors (1).
22319128063147 is an equidigital number, since it uses as much as digits as its factorization.
22319128063147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 870912, while the sum is 49.
The spelling of 22319128063147 in words is "twenty-two trillion, three hundred nineteen billion, one hundred twenty-eight million, sixty-three thousand, one hundred forty-seven".
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