Base | Representation |
---|---|
bin | 1010001001111101010110… |
… | …00001101010010100101101 |
3 | 2221001221211122122221212020 |
4 | 11010332223001222110231 |
5 | 10411343231000430331 |
6 | 115255210453100353 |
7 | 4463314540402245 |
oct | 504765301522455 |
9 | 87057748587766 |
10 | 22332404311341 |
11 | 7130135035913 |
12 | 26082050276b9 |
13 | c5cc23ba6c17 |
14 | 572c7371ab25 |
15 | 28adb5274c96 |
hex | 144fab06a52d |
22332404311341 has 32 divisors (see below), whose sum is σ = 30119601423360. Its totient is φ = 14717742695424.
The previous prime is 22332404311319. The next prime is 22332404311379. The reversal of 22332404311341 is 14311340423322.
It is not a de Polignac number, because 22332404311341 - 25 = 22332404311309 is a prime.
It is a super-2 number, since 2×223324043113412 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (22332404311741) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 668078070 + ... + 668111496.
It is an arithmetic number, because the mean of its divisors is an integer number (941237544480).
Almost surely, 222332404311341 is an apocalyptic number.
It is an amenable number.
22332404311341 is a deficient number, since it is larger than the sum of its proper divisors (7787197112019).
22332404311341 is a wasteful number, since it uses less digits than its factorization.
22332404311341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40865.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 22332404311341 its reverse (14311340423322), we get a palindrome (36643744734663).
The spelling of 22332404311341 in words is "twenty-two trillion, three hundred thirty-two billion, four hundred four million, three hundred eleven thousand, three hundred forty-one".
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