Base | Representation |
---|---|
bin | 100000100110010110010… |
… | …101001111110100000011 |
3 | 21221011100101201212221210 |
4 | 200212112111033310003 |
5 | 243200412212112121 |
6 | 4433044515021203 |
7 | 320564150531631 |
oct | 40462625176403 |
9 | 7834311655853 |
10 | 2240200113411 |
11 | 794077620207 |
12 | 3021ba59a803 |
13 | 13333322c8b0 |
14 | 7a5d7950351 |
15 | 3d4157b6876 |
hex | 2099654fd03 |
2240200113411 has 16 divisors (see below), whose sum is σ = 3221715883680. Its totient is φ = 1376433991680.
The previous prime is 2240200113409. The next prime is 2240200113433. The reversal of 2240200113411 is 1143110020422.
It is not a de Polignac number, because 2240200113411 - 21 = 2240200113409 is a prime.
It is a super-3 number, since 3×22402001134113 (a number of 38 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (2240200113611) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 44780796 + ... + 44830793.
It is an arithmetic number, because the mean of its divisors is an integer number (201357242730).
Almost surely, 22240200113411 is an apocalyptic number.
2240200113411 is a deficient number, since it is larger than the sum of its proper divisors (981515770269).
2240200113411 is a wasteful number, since it uses less digits than its factorization.
2240200113411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 89612246.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 2240200113411 its reverse (1143110020422), we get a palindrome (3383310133833).
The spelling of 2240200113411 in words is "two trillion, two hundred forty billion, two hundred million, one hundred thirteen thousand, four hundred eleven".
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