2240221130041 has 2 divisors, whose sum is σ = 2240221130042. Its totient is φ = 2240221130040.

The previous prime is 2240221129943. The next prime is 2240221130047. The reversal of 2240221130041 is 1400311220422.

2240221130041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2158651485225 + 81569644816 = 1469235^2 + 285604^2 .

It is a cyclic number.

It is not a de Polignac number, because 2240221130041 - 2²¹ = 2240219032889 is a prime.

It is a super-2 number, since 2×2240221130041² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2240221129994 and 2240221130021.

It is not a weakly prime, because it can be changed into another prime (2240221130047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1120110565020 + 1120110565021.

It is an arithmetic number, because the mean of its divisors is an integer number (1120110565021).

Almost surely, 2^{2240221130041} is an apocalyptic number.

It is an amenable number.

2240221130041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2240221130041 is an equidigital number, since it uses as much as digits as its factorization.

2240221130041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 22.

Adding to 2240221130041 its reverse (1400311220422), we get a palindrome (3640532350463).

The spelling of 2240221130041 in words is "two trillion, two hundred forty billion, two hundred twenty-one million, one hundred thirty thousand, forty-one".