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22424420113 = 71315836903
BaseRepresentation
bin10100111000100110…
…010111111100010001
32010212210111120102021
4110320212113330101
5331411122420423
614145053051441
71422461266054
oct247046277421
963783446367
1022424420113
119568000807
124419a86b81
132164a63854
14112a2a0a9b
158b3a1795d
hex538997f11

22424420113 has 4 divisors (see below), whose sum is σ = 22740257088. Its totient is φ = 22108583140.

The previous prime is 22424420107. The next prime is 22424420159. The reversal of 22424420113 is 31102442422.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31102442422 = 215551221211.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-22424420113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (22424429113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 157918381 + ... + 157918522.

It is an arithmetic number, because the mean of its divisors is an integer number (5685064272).

Almost surely, 222424420113 is an apocalyptic number.

It is an amenable number.

22424420113 is a deficient number, since it is larger than the sum of its proper divisors (315836975).

22424420113 is an equidigital number, since it uses as much as digits as its factorization.

22424420113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 315836974.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 22424420113 its reverse (31102442422), we get a palindrome (53526862535).

The spelling of 22424420113 in words is "twenty-two billion, four hundred twenty-four million, four hundred twenty thousand, one hundred thirteen".

Divisors: 1 71 315836903 22424420113