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2244131424113 is a prime number
BaseRepresentation
bin100000101010000000101…
…010000000011101110001
321221112111101012011101212
4200222000222000131301
5243231440121032423
64434534552405505
7321063445241105
oct40520052003561
97845441164355
102244131424113
11795804759117
12302b170a6895
1313380b851247
147a88bb03905
153d5959be578
hex20a80a80771

2244131424113 has 2 divisors, whose sum is σ = 2244131424114. Its totient is φ = 2244131424112.

The previous prime is 2244131424077. The next prime is 2244131424121. The reversal of 2244131424113 is 3114241314422.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1910634414049 + 333497010064 = 1382257^2 + 577492^2 .

It is a cyclic number.

It is not a de Polignac number, because 2244131424113 - 214 = 2244131407729 is a prime.

It is a super-2 number, since 2×22441314241132 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2244131424113.

It is not a weakly prime, because it can be changed into another prime (2244131424133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1122065712056 + 1122065712057.

It is an arithmetic number, because the mean of its divisors is an integer number (1122065712057).

Almost surely, 22244131424113 is an apocalyptic number.

It is an amenable number.

2244131424113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2244131424113 is an equidigital number, since it uses as much as digits as its factorization.

2244131424113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 18432, while the sum is 32.

Adding to 2244131424113 its reverse (3114241314422), we get a palindrome (5358372738535).

The spelling of 2244131424113 in words is "two trillion, two hundred forty-four billion, one hundred thirty-one million, four hundred twenty-four thousand, one hundred thirteen".