Base | Representation |
---|---|
bin | 100000101111100010001… |
… | …110010100100111011001 |
3 | 21222002210210001201211211 |
4 | 200233202032110213121 |
5 | 243331112201113311 |
6 | 4441355333223121 |
7 | 321363444331051 |
oct | 40574216244731 |
9 | 7862723051754 |
10 | 2250063301081 |
11 | 798279090082 |
12 | 3040b1791aa1 |
13 | 13424578790b |
14 | 7ac9185c561 |
15 | 3d7e164c821 |
hex | 20be23949d9 |
2250063301081 has 2 divisors, whose sum is σ = 2250063301082. Its totient is φ = 2250063301080.
The previous prime is 2250063301049. The next prime is 2250063301153. The reversal of 2250063301081 is 1801033600522.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1818303918025 + 431759383056 = 1348445^2 + 657084^2 .
It is a cyclic number.
It is not a de Polignac number, because 2250063301081 - 25 = 2250063301049 is a prime.
It is a super-2 number, since 2×22500633010812 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2250063305081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1125031650540 + 1125031650541.
It is an arithmetic number, because the mean of its divisors is an integer number (1125031650541).
Almost surely, 22250063301081 is an apocalyptic number.
It is an amenable number.
2250063301081 is a deficient number, since it is larger than the sum of its proper divisors (1).
2250063301081 is an equidigital number, since it uses as much as digits as its factorization.
2250063301081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 31.
The spelling of 2250063301081 in words is "two trillion, two hundred fifty billion, sixty-three million, three hundred one thousand, eighty-one".
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