Base | Representation |
---|---|
bin | 10101011010111110… |
… | …010110100001101001 |
3 | 2012100222200112011221 |
4 | 111122332112201221 |
5 | 334101242143423 |
6 | 14322214022041 |
7 | 1442663250202 |
oct | 253276264151 |
9 | 65328615157 |
10 | 23001131113 |
11 | 98335a2274 |
12 | 455b047921 |
13 | 2227396c6c |
14 | 1182b045a9 |
15 | 8e9484e5d |
hex | 55af96869 |
23001131113 has 2 divisors, whose sum is σ = 23001131114. Its totient is φ = 23001131112.
The previous prime is 23001131107. The next prime is 23001131149. The reversal of 23001131113 is 31113110032.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19603640169 + 3397490944 = 140013^2 + 58288^2 .
It is a cyclic number.
It is not a de Polignac number, because 23001131113 - 233 = 14411196521 is a prime.
It is not a weakly prime, because it can be changed into another prime (23001132113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11500565556 + 11500565557.
It is an arithmetic number, because the mean of its divisors is an integer number (11500565557).
Almost surely, 223001131113 is an apocalyptic number.
It is an amenable number.
23001131113 is a deficient number, since it is larger than the sum of its proper divisors (1).
23001131113 is an equidigital number, since it uses as much as digits as its factorization.
23001131113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 23001131113 its reverse (31113110032), we get a palindrome (54114241145).
The spelling of 23001131113 in words is "twenty-three billion, one million, one hundred thirty-one thousand, one hundred thirteen".
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