Base | Representation |
---|---|
bin | 100001011110001111010… |
… | …100110100011111011011 |
3 | 22010220020201212211111201 |
4 | 201132033110310133123 |
5 | 300141313244300011 |
6 | 4520411452135031 |
7 | 325120254164035 |
oct | 41361724643733 |
9 | 8126221784451 |
10 | 2300212103131 |
11 | 807572847328 |
12 | 311968467477 |
13 | 138ba82c7197 |
14 | 7d48bc44c55 |
15 | 3ec790d6cc1 |
hex | 2178f5347db |
2300212103131 has 2 divisors, whose sum is σ = 2300212103132. Its totient is φ = 2300212103130.
The previous prime is 2300212103071. The next prime is 2300212103207. The reversal of 2300212103131 is 1313012120032.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2300212103131 - 241 = 101188847579 is a prime.
It is a super-2 number, since 2×23002121031312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2300212103099 and 2300212103108.
It is not a weakly prime, because it can be changed into another prime (2300212103531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1150106051565 + 1150106051566.
It is an arithmetic number, because the mean of its divisors is an integer number (1150106051566).
Almost surely, 22300212103131 is an apocalyptic number.
2300212103131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2300212103131 is an equidigital number, since it uses as much as digits as its factorization.
2300212103131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 2300212103131 its reverse (1313012120032), we get a palindrome (3613224223163).
The spelling of 2300212103131 in words is "two trillion, three hundred billion, two hundred twelve million, one hundred three thousand, one hundred thirty-one".
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