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2300212113 = 31795997151
BaseRepresentation
bin1000100100011010…
…0111001110010001
312221022020212211020
42021012213032101
514202323241423
61020125310053
7111000323523
oct21106471621
95838225736
102300212113
11a80456451
12542405329
132a871a874
1417b6c5a13
15d6e144e3
hex891a7391

2300212113 has 16 divisors (see below), whose sum is σ = 3089664000. Its totient is φ = 1522149200.

The previous prime is 2300212099. The next prime is 2300212133. The reversal of 2300212113 is 3112120032.

It is a cyclic number.

It is not a de Polignac number, because 2300212113 - 24 = 2300212097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2300212092 and 2300212101.

It is not an unprimeable number, because it can be changed into a prime (2300212133) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 318088 + ... + 325238.

It is an arithmetic number, because the mean of its divisors is an integer number (193104000).

Almost surely, 22300212113 is an apocalyptic number.

It is an amenable number.

2300212113 is a deficient number, since it is larger than the sum of its proper divisors (789451887).

2300212113 is a wasteful number, since it uses less digits than its factorization.

2300212113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7932.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 2300212113 is about 47960.5266130388. The cubic root of 2300212113 is about 1320.0466988759.

Adding to 2300212113 its reverse (3112120032), we get a palindrome (5412332145).

The spelling of 2300212113 in words is "two billion, three hundred million, two hundred twelve thousand, one hundred thirteen".

Divisors: 1 3 179 537 599 1797 7151 21453 107221 321663 1280029 3840087 4283449 12850347 766737371 2300212113