Base | Representation |
---|---|
bin | 110100010100101100000100… |
… | …101110101110101111011011 |
3 | 1010011210021021200002101012221 |
4 | 310110230010232232233123 |
5 | 220130242012310030243 |
6 | 2133231421304444511 |
7 | 66320426253062446 |
oct | 6424540456565733 |
9 | 1104707250071187 |
10 | 230120132111323 |
11 | 673614443a2733 |
12 | 219869a6779737 |
13 | 9b5330a08cc6c |
14 | 40b7c33aa665d |
15 | 1b90e45717bed |
hex | d14b04baebdb |
230120132111323 has 4 divisors (see below), whose sum is σ = 230120170023240. Its totient is φ = 230120094199408.
The previous prime is 230120132111263. The next prime is 230120132111327. The reversal of 230120132111323 is 323111231021032.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 230120132111323 - 229 = 230119595240411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (230120132111327) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7572490 + ... + 22750447.
It is an arithmetic number, because the mean of its divisors is an integer number (57530042505810).
Almost surely, 2230120132111323 is an apocalyptic number.
230120132111323 is a deficient number, since it is larger than the sum of its proper divisors (37911917).
230120132111323 is an equidigital number, since it uses as much as digits as its factorization.
230120132111323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37911916.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 230120132111323 its reverse (323111231021032), we get a palindrome (553231363132355).
The spelling of 230120132111323 in words is "two hundred thirty trillion, one hundred twenty billion, one hundred thirty-two million, one hundred eleven thousand, three hundred twenty-three".
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