Base | Representation |
---|---|
bin | 100001100000010100001… |
… | …011110100001000110001 |
3 | 22011010000002011012222221 |
4 | 201200110023310020301 |
5 | 300210344411041423 |
6 | 4521420555401041 |
7 | 325226431353352 |
oct | 41402413641061 |
9 | 8133002135887 |
10 | 2302441112113 |
11 | 808506a8a80a |
12 | 31228aa53181 |
13 | 1391720446cc |
14 | 7d61dcb3d29 |
15 | 3ed59b33e5d |
hex | 218142f4231 |
2302441112113 has 2 divisors, whose sum is σ = 2302441112114. Its totient is φ = 2302441112112.
The previous prime is 2302441112093. The next prime is 2302441112117. The reversal of 2302441112113 is 3112111442032.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1721388608289 + 581052503824 = 1312017^2 + 762268^2 .
It is a cyclic number.
It is not a de Polignac number, because 2302441112113 - 233 = 2293851177521 is a prime.
It is not a weakly prime, because it can be changed into another prime (2302441112117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1151220556056 + 1151220556057.
It is an arithmetic number, because the mean of its divisors is an integer number (1151220556057).
Almost surely, 22302441112113 is an apocalyptic number.
It is an amenable number.
2302441112113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2302441112113 is an equidigital number, since it uses as much as digits as its factorization.
2302441112113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 2302441112113 its reverse (3112111442032), we get a palindrome (5414552554145).
The spelling of 2302441112113 in words is "two trillion, three hundred two billion, four hundred forty-one million, one hundred twelve thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •