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2303333012113 = 7329047573159
BaseRepresentation
bin100001100001001001010…
…110001001001010010001
322011012022020102102210021
4201201021112021022101
5300214211222341423
64522045300103441
7325260511365040
oct41411126111221
98135266372707
102303333012113
1180892448a451
12312499694b81
13139284a632a3
147d6a6522557
153edad0b095d
hex21849589291

2303333012113 has 4 divisors (see below), whose sum is σ = 2632380585280. Its totient is φ = 1974285438948.

The previous prime is 2303333012107. The next prime is 2303333012131. The reversal of 2303333012113 is 3112103333032.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2303333012113 - 229 = 2302796141201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2303333012413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 164523786573 + ... + 164523786586.

It is an arithmetic number, because the mean of its divisors is an integer number (658095146320).

Almost surely, 22303333012113 is an apocalyptic number.

It is an amenable number.

2303333012113 is a deficient number, since it is larger than the sum of its proper divisors (329047573167).

2303333012113 is an equidigital number, since it uses as much as digits as its factorization.

2303333012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 329047573166.

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 2303333012113 its reverse (3112103333032), we get a palindrome (5415436345145).

The spelling of 2303333012113 in words is "two trillion, three hundred three billion, three hundred thirty-three million, twelve thousand, one hundred thirteen".

Divisors: 1 7 329047573159 2303333012113