23041211131 has 4 divisors (see below), whose sum is σ = 23049688000. Its totient is φ = 23032734264.

The previous prime is 23041211107. The next prime is 23041211257. The reversal of 23041211131 is 13111214032.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 23041211131 - 2⁷ = 23041211003 is a prime.

It is a super-2 number, since 2×23041211131² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23041211099 and 23041211108.

It is not an unprimeable number, because it can be changed into a prime (23041251131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4234356 + ... + 4239793.

It is an arithmetic number, because the mean of its divisors is an integer number (5762422000).

Almost surely, 2^23041211131 is an apocalyptic number.

23041211131 is a deficient number, since it is larger than the sum of its proper divisors (8476869).

23041211131 is an equidigital number, since it uses as much as digits as its factorization.

23041211131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8476868.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 23041211131 its reverse (13111214032), we get a palindrome (36152425163).

The spelling of 23041211131 in words is "twenty-three billion, forty-one million, two hundred eleven thousand, one hundred thirty-one".