23042525433 has 4 divisors (see below), whose sum is σ = 30723367248. Its totient is φ = 15361683620.

The previous prime is 23042525431. The next prime is 23042525449. The reversal of 23042525433 is 33452524032.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23042525433 - 2¹ = 23042525431 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 23042525394 and 23042525403.

It is not an unprimeable number, because it can be changed into a prime (23042525431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3840420903 + ... + 3840420908.

It is an arithmetic number, because the mean of its divisors is an integer number (7680841812).

Almost surely, 2^23042525433 is an apocalyptic number.

It is an amenable number.

23042525433 is a deficient number, since it is larger than the sum of its proper divisors (7680841815).

23042525433 is an equidigital number, since it uses as much as digits as its factorization.

23042525433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7680841814.

The product of its (nonzero) digits is 86400, while the sum is 33.

The spelling of 23042525433 in words is "twenty-three billion, forty-two million, five hundred twenty-five thousand, four hundred thirty-three".