Base | Representation |
---|---|
bin | 1010011110101001001110… |
… | …11000110010010100001011 |
3 | 10000120220102110112211112211 |
4 | 11033110213120302110023 |
5 | 11010014343022231021 |
6 | 121001514241445551 |
7 | 4565545665146032 |
oct | 517244730622413 |
9 | 100526373484484 |
10 | 23043160352011 |
11 | 7384605315018 |
12 | 2701b039408b7 |
13 | cb1c64862467 |
14 | 59941b349719 |
15 | 29e61377c3e1 |
hex | 14f52763250b |
23043160352011 has 2 divisors, whose sum is σ = 23043160352012. Its totient is φ = 23043160352010.
The previous prime is 23043160351993. The next prime is 23043160352041. The reversal of 23043160352011 is 11025306134032.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23043160352011 - 241 = 20844137096459 is a prime.
It is a super-4 number, since 4×230431603520114 (a number of 55 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (23043160352041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11521580176005 + 11521580176006.
It is an arithmetic number, because the mean of its divisors is an integer number (11521580176006).
Almost surely, 223043160352011 is an apocalyptic number.
23043160352011 is a deficient number, since it is larger than the sum of its proper divisors (1).
23043160352011 is an equidigital number, since it uses as much as digits as its factorization.
23043160352011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 23043160352011 its reverse (11025306134032), we get a palindrome (34068466486043).
The spelling of 23043160352011 in words is "twenty-three trillion, forty-three billion, one hundred sixty million, three hundred fifty-two thousand, eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •