23043314131 has 4 divisors (see below), whose sum is σ = 23837911200. Its totient is φ = 22248717064.

The previous prime is 23043314123. The next prime is 23043314137. The reversal of 23043314131 is 13141334032.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 23043314131 - 2³ = 23043314123 is a prime.

It is a super-2 number, since 2×23043314131² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23043314096 and 23043314105.

It is not an unprimeable number, because it can be changed into a prime (23043314137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 397298491 + ... + 397298548.

It is an arithmetic number, because the mean of its divisors is an integer number (5959477800).

Almost surely, 2^23043314131 is an apocalyptic number.

23043314131 is a deficient number, since it is larger than the sum of its proper divisors (794597069).

23043314131 is an equidigital number, since it uses as much as digits as its factorization.

23043314131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 794597068.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 23043314131 its reverse (13141334032), we get a palindrome (36184648163).

The spelling of 23043314131 in words is "twenty-three billion, forty-three million, three hundred fourteen thousand, one hundred thirty-one".