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23043321213001 is a prime number
BaseRepresentation
bin1010011110101001100001…
…11110011011000001001001
310000120220211200020102100021
411033110300332123001021
511010020210212304001
6121001542225340441
74565552660352355
oct517246076330111
9100526750212307
1023043321213001
1173846880a5291
122701b49797721
13cb1c8bc94a8b
14599434860465
1529e622954ba1
hex14f530f9b049

23043321213001 has 2 divisors, whose sum is σ = 23043321213002. Its totient is φ = 23043321213000.

The previous prime is 23043321212969. The next prime is 23043321213013. The reversal of 23043321213001 is 10031212334032.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22356206215225 + 687114997776 = 4728235^2 + 828924^2 .

It is a cyclic number.

It is not a de Polignac number, because 23043321213001 - 25 = 23043321212969 is a prime.

It is a super-2 number, since 2×230433212130012 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (23043321213041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11521660606500 + 11521660606501.

It is an arithmetic number, because the mean of its divisors is an integer number (11521660606501).

Almost surely, 223043321213001 is an apocalyptic number.

It is an amenable number.

23043321213001 is a deficient number, since it is larger than the sum of its proper divisors (1).

23043321213001 is an equidigital number, since it uses as much as digits as its factorization.

23043321213001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 23043321213001 its reverse (10031212334032), we get a palindrome (33074533547033).

The spelling of 23043321213001 in words is "twenty-three trillion, forty-three billion, three hundred twenty-one million, two hundred thirteen thousand, one".