Base | Representation |
---|---|
bin | 100001100010001010001… |
… | …101010101000001010001 |
3 | 22011022010002002010222010 |
4 | 201202022031111001101 |
5 | 300223423313023213 |
6 | 4522345252133133 |
7 | 325326464120043 |
oct | 41421215250121 |
9 | 8138102063863 |
10 | 2304421220433 |
11 | 809332780472 |
12 | 3127420071a9 |
13 | 1393c9345a37 |
14 | 7d76ac71a93 |
15 | 3ee238b7ac3 |
hex | 2188a355051 |
2304421220433 has 16 divisors (see below), whose sum is σ = 3125092988160. Its totient is φ = 1510022700816.
The previous prime is 2304421220401. The next prime is 2304421220441. The reversal of 2304421220433 is 3340221244032.
It is not a de Polignac number, because 2304421220433 - 25 = 2304421220401 is a prime.
It is a super-2 number, since 2×23044212204332 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2304421220433.
It is not an unprimeable number, because it can be changed into a prime (2304421228433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 280066 + ... + 2165012.
It is an arithmetic number, because the mean of its divisors is an integer number (195318311760).
Almost surely, 22304421220433 is an apocalyptic number.
It is an amenable number.
2304421220433 is a deficient number, since it is larger than the sum of its proper divisors (820671767727).
2304421220433 is a wasteful number, since it uses less digits than its factorization.
2304421220433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1891916.
The product of its (nonzero) digits is 27648, while the sum is 30.
Adding to 2304421220433 its reverse (3340221244032), we get a palindrome (5644642464465).
The spelling of 2304421220433 in words is "two trillion, three hundred four billion, four hundred twenty-one million, two hundred twenty thousand, four hundred thirty-three".
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