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23052131144531 is a prime number
BaseRepresentation
bin1010011110111001111100…
…00101101001001101010011
310000121202120122200022102122
411033130332011221031103
511010141231033111111
6121010000341004455
74566314204502056
oct517347605511523
9100552518608378
1023052131144531
117388399077235
1227037a80b372b
13cb2a64257408
14599a2c91aa9d
1529e98b0d9cdb
hex14f73e169353

23052131144531 has 2 divisors, whose sum is σ = 23052131144532. Its totient is φ = 23052131144530.

The previous prime is 23052131144473. The next prime is 23052131144561. The reversal of 23052131144531 is 13544113125032.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 23052131144531 - 26 = 23052131144467 is a prime.

It is a super-3 number, since 3×230521311445313 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 23052131144491 and 23052131144500.

It is not a weakly prime, because it can be changed into another prime (23052131144561) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11526065572265 + 11526065572266.

It is an arithmetic number, because the mean of its divisors is an integer number (11526065572266).

Almost surely, 223052131144531 is an apocalyptic number.

23052131144531 is a deficient number, since it is larger than the sum of its proper divisors (1).

23052131144531 is an equidigital number, since it uses as much as digits as its factorization.

23052131144531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 35.

Adding to 23052131144531 its reverse (13544113125032), we get a palindrome (36596244269563).

The spelling of 23052131144531 in words is "twenty-three trillion, fifty-two billion, one hundred thirty-one million, one hundred forty-four thousand, five hundred thirty-one".