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23055344120043 = 325348334054759
BaseRepresentation
bin1010011110111111111011…
…00110001011000011101011
310000122001212120110101020200
411033133331212023003223
511010214321043320133
6121011251234123243
74566456630363444
oct517377546130353
9100561776411220
1023055344120043
1173897977822a4
122704344120523
13cb3156ab9c61
14599c555222cb
1529eac81ec913
hex14f7fd98b0eb

23055344120043 has 12 divisors (see below), whose sum is σ = 33930506441520. Its totient is φ = 15080225084496.

The previous prime is 23055344120041. The next prime is 23055344120069. The reversal of 23055344120043 is 34002144355032.

23055344120043 is a `hidden beast` number, since 2 + 3 + 0 + 5 + 5 + 3 + 441 + 200 + 4 + 3 = 666.

It is not a de Polignac number, because 23055344120043 - 21 = 23055344120041 is a prime.

It is not an unprimeable number, because it can be changed into a prime (23055344120041) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 24167026903 + ... + 24167027856.

It is an arithmetic number, because the mean of its divisors is an integer number (2827542203460).

Almost surely, 223055344120043 is an apocalyptic number.

23055344120043 is a deficient number, since it is larger than the sum of its proper divisors (10875162321477).

23055344120043 is a wasteful number, since it uses less digits than its factorization.

23055344120043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48334054818 (or 48334054815 counting only the distinct ones).

The product of its (nonzero) digits is 172800, while the sum is 36.

Adding to 23055344120043 its reverse (34002144355032), we get a palindrome (57057488475075).

The spelling of 23055344120043 in words is "twenty-three trillion, fifty-five billion, three hundred forty-four million, one hundred twenty thousand, forty-three".

Divisors: 1 3 9 53 159 477 48334054759 145002164277 435006492831 2561704902227 7685114706681 23055344120043