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23100102011017 is a prime number
BaseRepresentation
bin1010100000010011010010…
…10111111110100010001001
310000210100101211022211011101
411100021221113332202021
511011433002103323032
6121044012415101401
74602633030233503
oct520115127764211
9100710354284141
1023100102011017
1173a6775404239
122710b55511861
13cb743a7bc305
1459c09d96ad73
152a0d47764de7
hex1502695fe889

23100102011017 has 2 divisors, whose sum is σ = 23100102011018. Its totient is φ = 23100102011016.

The previous prime is 23100102010933. The next prime is 23100102011039. The reversal of 23100102011017 is 71011020100132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19767947485456 + 3332154525561 = 4446116^2 + 1825419^2 .

It is a cyclic number.

It is not a de Polignac number, because 23100102011017 - 223 = 23100093622409 is a prime.

It is a super-2 number, since 2×231001020110172 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 23100102010985 and 23100102011003.

It is not a weakly prime, because it can be changed into another prime (23100102011057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11550051005508 + 11550051005509.

It is an arithmetic number, because the mean of its divisors is an integer number (11550051005509).

Almost surely, 223100102011017 is an apocalyptic number.

It is an amenable number.

23100102011017 is a deficient number, since it is larger than the sum of its proper divisors (1).

23100102011017 is an equidigital number, since it uses as much as digits as its factorization.

23100102011017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84, while the sum is 19.

Adding to 23100102011017 its reverse (71011020100132), we get a palindrome (94111122111149).

The spelling of 23100102011017 in words is "twenty-three trillion, one hundred billion, one hundred two million, eleven thousand, seventeen".