Base | Representation |
---|---|
bin | 1010100000010100000010… |
… | …11010111100100001100011 |
3 | 10000210101102221110020222120 |
4 | 11100022001122330201203 |
5 | 11011434313343124103 |
6 | 121044120430035323 |
7 | 4602646026316344 |
oct | 520120132744143 |
9 | 100711387406876 |
10 | 23100505442403 |
11 | 73a6962103204 |
12 | 2711048648b43 |
13 | cb74a32626cc |
14 | 59c0db3860cb |
15 | 2a0d6cda5253 |
hex | 1502816bc863 |
23100505442403 has 4 divisors (see below), whose sum is σ = 30800673923208. Its totient is φ = 15400336961600.
The previous prime is 23100505442383. The next prime is 23100505442431. The reversal of 23100505442403 is 30424450500132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23100505442403 - 234 = 23083325573219 is a prime.
It is not an unprimeable number, because it can be changed into a prime (23100505442453) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3850084240398 + ... + 3850084240403.
It is an arithmetic number, because the mean of its divisors is an integer number (7700168480802).
Almost surely, 223100505442403 is an apocalyptic number.
23100505442403 is a deficient number, since it is larger than the sum of its proper divisors (7700168480805).
23100505442403 is an equidigital number, since it uses as much as digits as its factorization.
23100505442403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7700168480804.
The product of its (nonzero) digits is 57600, while the sum is 33.
Adding to 23100505442403 its reverse (30424450500132), we get a palindrome (53524955942535).
The spelling of 23100505442403 in words is "twenty-three trillion, one hundred billion, five hundred five million, four hundred forty-two thousand, four hundred three".
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