Base | Representation |
---|---|
bin | 110100100001101010111110… |
… | …110111001010011100011001 |
3 | 1010021221120011022001021002101 |
4 | 310201222332313022130121 |
5 | 220234401204124130033 |
6 | 2135153331440003401 |
7 | 66442042321346536 |
oct | 6441527667123431 |
9 | 1107846138037071 |
10 | 231012313114393 |
11 | 67675854302398 |
12 | 21aab898300561 |
13 | 9bb94a196b565 |
14 | 41090ac85dd8d |
15 | 1ba926159e97d |
hex | d21abedca719 |
231012313114393 has 2 divisors, whose sum is σ = 231012313114394. Its totient is φ = 231012313114392.
The previous prime is 231012313114361. The next prime is 231012313114411. The reversal of 231012313114393 is 393411313210132.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 116874542587609 + 114137770526784 = 10810853^2 + 10683528^2 .
It is a cyclic number.
It is not a de Polignac number, because 231012313114393 - 25 = 231012313114361 is a prime.
It is not a weakly prime, because it can be changed into another prime (231012313114343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115506156557196 + 115506156557197.
It is an arithmetic number, because the mean of its divisors is an integer number (115506156557197).
Almost surely, 2231012313114393 is an apocalyptic number.
It is an amenable number.
231012313114393 is a deficient number, since it is larger than the sum of its proper divisors (1).
231012313114393 is an equidigital number, since it uses as much as digits as its factorization.
231012313114393 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 37.
The spelling of 231012313114393 in words is "two hundred thirty-one trillion, twelve billion, three hundred thirteen million, one hundred fourteen thousand, three hundred ninety-three".
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