Base | Representation |
---|---|
bin | 1101011100100101110… |
… | …1000101010011011011 |
3 | 211002021200220221220021 |
4 | 3113021131011103123 |
5 | 12241103324023003 |
6 | 254043112411311 |
7 | 22455502021153 |
oct | 3271135052333 |
9 | 732250827807 |
10 | 231013111003 |
11 | 89a76973554 |
12 | 389319a6b37 |
13 | 18a2756202c |
14 | b276ccb763 |
15 | 6020ebe2bd |
hex | 35c97454db |
231013111003 has 2 divisors, whose sum is σ = 231013111004. Its totient is φ = 231013111002.
The previous prime is 231013110917. The next prime is 231013111013. The reversal of 231013111003 is 300111310132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 231013111003 - 213 = 231013102811 is a prime.
It is not a weakly prime, because it can be changed into another prime (231013111013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115506555501 + 115506555502.
It is an arithmetic number, because the mean of its divisors is an integer number (115506555502).
Almost surely, 2231013111003 is an apocalyptic number.
231013111003 is a deficient number, since it is larger than the sum of its proper divisors (1).
231013111003 is an equidigital number, since it uses as much as digits as its factorization.
231013111003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 231013111003 its reverse (300111310132), we get a palindrome (531124421135).
The spelling of 231013111003 in words is "two hundred thirty-one billion, thirteen million, one hundred eleven thousand, three".
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