Base | Representation |
---|---|
bin | 10101100000111111… |
… | …001000101101111001 |
3 | 2012122000111012021101 |
4 | 111200333020231321 |
5 | 334303102444433 |
6 | 14340220011401 |
7 | 1445326521442 |
oct | 254077105571 |
9 | 65560435241 |
10 | 23101999993 |
11 | 9885527586 |
12 | 4588990b61 |
13 | 22422530a7 |
14 | 11922802c9 |
15 | 90325c07d |
hex | 560fc8b79 |
23101999993 has 2 divisors, whose sum is σ = 23101999994. Its totient is φ = 23101999992.
The previous prime is 23101999919. The next prime is 23102000027. The reversal of 23101999993 is 39999910132.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18805459689 + 4296540304 = 137133^2 + 65548^2 .
It is a cyclic number.
It is not a de Polignac number, because 23101999993 - 217 = 23101868921 is a prime.
It is not a weakly prime, because it can be changed into another prime (23101999913) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11550999996 + 11550999997.
It is an arithmetic number, because the mean of its divisors is an integer number (11550999997).
Almost surely, 223101999993 is an apocalyptic number.
It is an amenable number.
23101999993 is a deficient number, since it is larger than the sum of its proper divisors (1).
23101999993 is an equidigital number, since it uses as much as digits as its factorization.
23101999993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1062882, while the sum is 55.
The spelling of 23101999993 in words is "twenty-three billion, one hundred one million, nine hundred ninety-nine thousand, nine hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •