Base | Representation |
---|---|
bin | 100001100111100010110… |
… | …001010011010111000011 |
3 | 22011212000221122211202002 |
4 | 201213202301103113003 |
5 | 300322243203404443 |
6 | 4525143034414215 |
7 | 325622650053044 |
oct | 41474261232703 |
9 | 8155027584662 |
10 | 2310202013123 |
11 | 81082989a594 |
12 | 313895b9136b |
13 | 139b0ab90b24 |
14 | 7db588dc8cb |
15 | 401611502b8 |
hex | 219e2c535c3 |
2310202013123 has 4 divisors (see below), whose sum is σ = 2317630315728. Its totient is φ = 2302773710520.
The previous prime is 2310202013113. The next prime is 2310202013143. The reversal of 2310202013123 is 3213102020132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2310202013123 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2310202013095 and 2310202013104.
It is not an unprimeable number, because it can be changed into a prime (2310202013113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3714150836 + ... + 3714151457.
It is an arithmetic number, because the mean of its divisors is an integer number (579407578932).
Almost surely, 22310202013123 is an apocalyptic number.
2310202013123 is a deficient number, since it is larger than the sum of its proper divisors (7428302605).
2310202013123 is an equidigital number, since it uses as much as digits as its factorization.
2310202013123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7428302604.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 2310202013123 its reverse (3213102020132), we get a palindrome (5523304033255).
The spelling of 2310202013123 in words is "two trillion, three hundred ten billion, two hundred two million, thirteen thousand, one hundred twenty-three".
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