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23102043113 = 151152993663
BaseRepresentation
bin10101100000111111…
…010011001111101001
32012122000120101102102
4111200333103033221
5334303110334423
614340220543145
71445330061242
oct254077231751
965560511372
1023102043113
119885556a16
1245889b1ab5
1322422698c6
141192291cc9
15903269c28
hex560fd33e9

23102043113 has 4 divisors (see below), whose sum is σ = 23255036928. Its totient is φ = 22949049300.

The previous prime is 23102043101. The next prime is 23102043197. The reversal of 23102043113 is 31134020132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23102043113 - 220 = 23100994537 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (23102033113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 76496681 + ... + 76496982.

It is an arithmetic number, because the mean of its divisors is an integer number (5813759232).

Almost surely, 223102043113 is an apocalyptic number.

It is an amenable number.

23102043113 is a deficient number, since it is larger than the sum of its proper divisors (152993815).

23102043113 is a wasteful number, since it uses less digits than its factorization.

23102043113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 152993814.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 23102043113 its reverse (31134020132), we get a palindrome (54236063245).

The spelling of 23102043113 in words is "twenty-three billion, one hundred two million, forty-three thousand, one hundred thirteen".

Divisors: 1 151 152993663 23102043113