Base | Representation |
---|---|
bin | 110100100001110101001101… |
… | …111011011110001001000011 |
3 | 1010021222121112020001120010100 |
4 | 310201311031323132021003 |
5 | 220240041211122221011 |
6 | 2135202350154133443 |
7 | 66442611551510640 |
oct | 6441651573361103 |
9 | 1107877466046110 |
10 | 231023303320131 |
11 | 6767a483a60653 |
12 | 21ab1a44a21283 |
13 | 9bba533846b8a |
14 | 4109832300dc7 |
15 | 1ba96a6356d56 |
hex | d21d4dede243 |
231023303320131 has 48 divisors (see below), whose sum is σ = 382052483317440. Its totient is φ = 131777708544000.
The previous prime is 231023303320097. The next prime is 231023303320133. The reversal of 231023303320131 is 131023303320132.
231023303320131 is a `hidden beast` number, since 2 + 3 + 1 + 0 + 2 + 3 + 303 + 320 + 1 + 31 = 666.
It is not a de Polignac number, because 231023303320131 - 211 = 231023303318083 is a prime.
It is a super-2 number, since 2×2310233033201312 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 231023303320095 and 231023303320104.
It is not an unprimeable number, because it can be changed into a prime (231023303320133) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1863014131 + ... + 1863138131.
It is an arithmetic number, because the mean of its divisors is an integer number (7959426735780).
Almost surely, 2231023303320131 is an apocalyptic number.
231023303320131 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
231023303320131 is a deficient number, since it is larger than the sum of its proper divisors (151029179997309).
231023303320131 is a wasteful number, since it uses less digits than its factorization.
231023303320131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 176556 (or 176553 counting only the distinct ones).
The product of its (nonzero) digits is 5832, while the sum is 27.
Adding to 231023303320131 its reverse (131023303320132), we get a palindrome (362046606640263).
Subtracting from 231023303320131 its reverse (131023303320132), we obtain a palindrome (99999999999999).
The spelling of 231023303320131 in words is "two hundred thirty-one trillion, twenty-three billion, three hundred three million, three hundred twenty thousand, one hundred thirty-one".
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