Base | Representation |
---|---|
bin | 100001100111101000110… |
… | …110011101110110010001 |
3 | 22011212022001121211201112 |
4 | 201213220312131312101 |
5 | 300323000312430342 |
6 | 4525201121143105 |
7 | 325625326145450 |
oct | 41475066356621 |
9 | 8155261554645 |
10 | 2310304030097 |
11 | 810881439438 |
12 | 31390418aa95 |
13 | 139b2605c6bb |
14 | 7db68296b97 |
15 | 4016a0a2682 |
hex | 219e8d9dd91 |
2310304030097 has 4 divisors (see below), whose sum is σ = 2640347462976. Its totient is φ = 1980260597220.
The previous prime is 2310304030093. The next prime is 2310304030129. The reversal of 2310304030097 is 7900304030132.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2310304030097 - 22 = 2310304030093 is a prime.
It is a super-2 number, since 2×23103040300972 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2310304030093) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 165021716429 + ... + 165021716442.
It is an arithmetic number, because the mean of its divisors is an integer number (660086865744).
Almost surely, 22310304030097 is an apocalyptic number.
It is an amenable number.
2310304030097 is a deficient number, since it is larger than the sum of its proper divisors (330043432879).
2310304030097 is an equidigital number, since it uses as much as digits as its factorization.
2310304030097 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 330043432878.
The product of its (nonzero) digits is 13608, while the sum is 32.
The spelling of 2310304030097 in words is "two trillion, three hundred ten billion, three hundred four million, thirty thousand, ninety-seven".
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