Base | Representation |
---|---|
bin | 1010100000011011010100… |
… | …01001110100001101000001 |
3 | 10000210202112001122112022221 |
4 | 11100031222021310031001 |
5 | 11012020312432340301 |
6 | 121050004111131041 |
7 | 4603144551012214 |
oct | 520155211641501 |
9 | 100722461575287 |
10 | 23104410043201 |
11 | 73a8586158613 |
12 | 2711958213a81 |
13 | cb7976191796 |
14 | 59c38bb8577b |
15 | 2a0eeaa83da1 |
hex | 15036a274341 |
23104410043201 has 2 divisors, whose sum is σ = 23104410043202. Its totient is φ = 23104410043200.
The previous prime is 23104410043193. The next prime is 23104410043219. The reversal of 23104410043201 is 10234001440132.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 21843247352976 + 1261162690225 = 4673676^2 + 1123015^2 .
It is a cyclic number.
It is not a de Polignac number, because 23104410043201 - 23 = 23104410043193 is a prime.
It is not a weakly prime, because it can be changed into another prime (23104410043501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11552205021600 + 11552205021601.
It is an arithmetic number, because the mean of its divisors is an integer number (11552205021601).
Almost surely, 223104410043201 is an apocalyptic number.
It is an amenable number.
23104410043201 is a deficient number, since it is larger than the sum of its proper divisors (1).
23104410043201 is an equidigital number, since it uses as much as digits as its factorization.
23104410043201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 23104410043201 its reverse (10234001440132), we get a palindrome (33338411483333).
The spelling of 23104410043201 in words is "twenty-three trillion, one hundred four billion, four hundred ten million, forty-three thousand, two hundred one".
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