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23110022014897 is a prime number
BaseRepresentation
bin1010100000100101110001…
…01001110010011110110001
310000211022000011120020020111
411100102320221302132301
511012113311113434042
6121052333023141321
74603433613666556
oct520227051623661
9100738004506214
1023110022014897
1173aa9a5a4aa54
122712a63744841
13cb835ba4b0ac
1459c761228a2d
152a12285c0517
hex1504b8a727b1

23110022014897 has 2 divisors, whose sum is σ = 23110022014898. Its totient is φ = 23110022014896.

The previous prime is 23110022014873. The next prime is 23110022014939. The reversal of 23110022014897 is 79841022001132.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14582080185201 + 8527941829696 = 3818649^2 + 2920264^2 .

It is a cyclic number.

It is not a de Polignac number, because 23110022014897 - 215 = 23110021982129 is a prime.

It is not a weakly prime, because it can be changed into another prime (23110022012897) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11555011007448 + 11555011007449.

It is an arithmetic number, because the mean of its divisors is an integer number (11555011007449).

Almost surely, 223110022014897 is an apocalyptic number.

It is an amenable number.

23110022014897 is a deficient number, since it is larger than the sum of its proper divisors (1).

23110022014897 is an equidigital number, since it uses as much as digits as its factorization.

23110022014897 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48384, while the sum is 40.

The spelling of 23110022014897 in words is "twenty-three trillion, one hundred ten billion, twenty-two million, fourteen thousand, eight hundred ninety-seven".