Base | Representation |
---|---|
bin | 10101100001011110… |
… | …001100110101001011 |
3 | 2012122120210220210121 |
4 | 111201132030311023 |
5 | 334312144041212 |
6 | 14341110324111 |
7 | 1445455656046 |
oct | 254136146513 |
9 | 65576726717 |
10 | 23110143307 |
11 | 988a089799 |
12 | 458b659637 |
13 | 2243b44814 |
14 | 119339dc5d |
15 | 903d19d07 |
hex | 56178cd4b |
23110143307 has 2 divisors, whose sum is σ = 23110143308. Its totient is φ = 23110143306.
The previous prime is 23110143253. The next prime is 23110143313. The reversal of 23110143307 is 70334101132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23110143307 - 219 = 23109619019 is a prime.
It is not a weakly prime, because it can be changed into another prime (23110143337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11555071653 + 11555071654.
It is an arithmetic number, because the mean of its divisors is an integer number (11555071654).
Almost surely, 223110143307 is an apocalyptic number.
23110143307 is a deficient number, since it is larger than the sum of its proper divisors (1).
23110143307 is an equidigital number, since it uses as much as digits as its factorization.
23110143307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 23110143307 its reverse (70334101132), we get a palindrome (93444244439).
The spelling of 23110143307 in words is "twenty-three billion, one hundred ten million, one hundred forty-three thousand, three hundred seven".
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