Base | Representation |
---|---|
bin | 1010100000101000001011… |
… | …00110111011010001010111 |
3 | 10000211102100010222122220110 |
4 | 11100110011212323101113 |
5 | 11012123432124010403 |
6 | 121053105103534103 |
7 | 4603510612061541 |
oct | 520240546732127 |
9 | 100742303878813 |
10 | 23111313110103 |
11 | 74004a8815989 |
12 | 2713163bba333 |
13 | cb8506388b5a |
14 | 59c8448ac691 |
15 | 2a12a1b02103 |
hex | 1505059bb457 |
23111313110103 has 16 divisors (see below), whose sum is σ = 30985735094496. Its totient is φ = 15322218808320.
The previous prime is 23111313110077. The next prime is 23111313110111. The reversal of 23111313110103 is 30101131311132.
It is not a de Polignac number, because 23111313110103 - 213 = 23111313101911 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 23111313110103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23111313110003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 50083075 + ... + 50542427.
It is an arithmetic number, because the mean of its divisors is an integer number (1936608443406).
Almost surely, 223111313110103 is an apocalyptic number.
23111313110103 is a deficient number, since it is larger than the sum of its proper divisors (7874421984393).
23111313110103 is a wasteful number, since it uses less digits than its factorization.
23111313110103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 552194.
The product of its (nonzero) digits is 162, while the sum is 21.
Adding to 23111313110103 its reverse (30101131311132), we get a palindrome (53212444421235).
The spelling of 23111313110103 in words is "twenty-three trillion, one hundred eleven billion, three hundred thirteen million, one hundred ten thousand, one hundred three".
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