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23111313131 = 27778322403
BaseRepresentation
bin10101100001100010…
…101010011011101011
32012122200000100111102
4111201202222123223
5334312444010011
614341151352015
71445501630444
oct254142523353
965580010442
1023111313131
11988a808695
12458bb2260b
13224416411a
1411935c62cb
15903e9b73b
hex5618aa6eb

23111313131 has 4 divisors (see below), whose sum is σ = 23119638312. Its totient is φ = 23102987952.

The previous prime is 23111313097. The next prime is 23111313151. The reversal of 23111313131 is 13131311132.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 23111313131 - 26 = 23111313067 is a prime.

It is a super-3 number, since 3×231113131313 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (23111313151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4158425 + ... + 4163978.

It is an arithmetic number, because the mean of its divisors is an integer number (5779909578).

Almost surely, 223111313131 is an apocalyptic number.

23111313131 is a deficient number, since it is larger than the sum of its proper divisors (8325181).

23111313131 is an equidigital number, since it uses as much as digits as its factorization.

23111313131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8325180.

The product of its digits is 162, while the sum is 20.

Adding to 23111313131 its reverse (13131311132), we get a palindrome (36242624263).

The spelling of 23111313131 in words is "twenty-three billion, one hundred eleven million, three hundred thirteen thousand, one hundred thirty-one".

Divisors: 1 2777 8322403 23111313131