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231113250042 = 23281137077847
BaseRepresentation
bin1101011100111101101…
…1000101010011111010
3211002112200100112211120
43113033123011103322
512241304443000132
6254101051010110
722461126132543
oct3271733052372
9732480315746
10231113250042
118a01844a494
123895b439936
1318a42223bbc
14b2863174ca
156029ba002c
hex35cf6c54fa

231113250042 has 16 divisors (see below), whose sum is σ = 463871437632. Its totient is φ = 76763593760.

The previous prime is 231113250023. The next prime is 231113250047. The reversal of 231113250042 is 240052311132.

It is a junction number, because it is equal to n+sod(n) for n = 231113249994 and 231113250021.

It is not an unprimeable number, because it can be changed into a prime (231113250047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 68537238 + ... + 68540609.

It is an arithmetic number, because the mean of its divisors is an integer number (28991964852).

Almost surely, 2231113250042 is an apocalyptic number.

231113250042 is an abundant number, since it is smaller than the sum of its proper divisors (232758187590).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

231113250042 is a wasteful number, since it uses less digits than its factorization.

231113250042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 137078133.

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 231113250042 its reverse (240052311132), we get a palindrome (471165561174).

The spelling of 231113250042 in words is "two hundred thirty-one billion, one hundred thirteen million, two hundred fifty thousand, forty-two".

Divisors: 1 2 3 6 281 562 843 1686 137077847 274155694 411233541 822467082 38518875007 77037750014 115556625021 231113250042