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2311143107953 is a prime number
BaseRepresentation
bin100001101000011010110…
…111010010110101110001
322011221110112111102011011
4201220122313102311301
5300331210113423303
64525420253350521
7325655165166541
oct41503267226561
98157415442134
102311143107953
11811172040009
12313ab9198441
13139c2ab45484
147dc078b5321
15401b8a9816d
hex21a1add2d71

2311143107953 has 2 divisors, whose sum is σ = 2311143107954. Its totient is φ = 2311143107952.

The previous prime is 2311143107939. The next prime is 2311143107963. The reversal of 2311143107953 is 3597013411132.

2311143107953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2154222546529 + 156920561424 = 1467727^2 + 396132^2 .

It is a cyclic number.

It is not a de Polignac number, because 2311143107953 - 229 = 2310606237041 is a prime.

It is not a weakly prime, because it can be changed into another prime (2311143107963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1155571553976 + 1155571553977.

It is an arithmetic number, because the mean of its divisors is an integer number (1155571553977).

Almost surely, 22311143107953 is an apocalyptic number.

It is an amenable number.

2311143107953 is a deficient number, since it is larger than the sum of its proper divisors (1).

2311143107953 is an equidigital number, since it uses as much as digits as its factorization.

2311143107953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 68040, while the sum is 40.

The spelling of 2311143107953 in words is "two trillion, three hundred eleven billion, one hundred forty-three million, one hundred seven thousand, nine hundred fifty-three".