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23112254041 is a prime number
BaseRepresentation
bin10101100001100110…
…010000001001011001
32012122201210011011221
4111201212100021121
5334313214112131
614341223452041
71445512626562
oct254146201131
965581704157
1023112254041
1198902a05a8
1245902b7021
132244403486
14119378d169
159040d5411
hex561990259

23112254041 has 2 divisors, whose sum is σ = 23112254042. Its totient is φ = 23112254040.

The previous prime is 23112254003. The next prime is 23112254057. The reversal of 23112254041 is 14045221132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17324087641 + 5788166400 = 131621^2 + 76080^2 .

It is a cyclic number.

It is not a de Polignac number, because 23112254041 - 29 = 23112253529 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 23112253997 and 23112254015.

It is not a weakly prime, because it can be changed into another prime (23112254441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11556127020 + 11556127021.

It is an arithmetic number, because the mean of its divisors is an integer number (11556127021).

Almost surely, 223112254041 is an apocalyptic number.

It is an amenable number.

23112254041 is a deficient number, since it is larger than the sum of its proper divisors (1).

23112254041 is an equidigital number, since it uses as much as digits as its factorization.

23112254041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 23112254041 its reverse (14045221132), we get a palindrome (37157475173).

The spelling of 23112254041 in words is "twenty-three billion, one hundred twelve million, two hundred fifty-four thousand, forty-one".