Base | Representation |
---|---|
bin | 100001101000100100001… |
… | …111011011100100011011 |
3 | 22011221212111112012120121 |
4 | 201220210033123210123 |
5 | 300332020402230412 |
6 | 4525444033334111 |
7 | 325662115333654 |
oct | 41504417334433 |
9 | 8157774465517 |
10 | 2311300430107 |
11 | 811242923519 |
12 | 313b41a07337 |
13 | 139c546090c6 |
14 | 7dc2074852b |
15 | 401c77c2107 |
hex | 21a243db91b |
2311300430107 has 4 divisors (see below), whose sum is σ = 2319467569720. Its totient is φ = 2303133290496.
The previous prime is 2311300430063. The next prime is 2311300430111. The reversal of 2311300430107 is 7010340031132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2311300430107 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2311300433107) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4083569382 + ... + 4083569947.
It is an arithmetic number, because the mean of its divisors is an integer number (579866892430).
Almost surely, 22311300430107 is an apocalyptic number.
2311300430107 is a deficient number, since it is larger than the sum of its proper divisors (8167139613).
2311300430107 is an equidigital number, since it uses as much as digits as its factorization.
2311300430107 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8167139612.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 2311300430107 its reverse (7010340031132), we get a palindrome (9321640461239).
The spelling of 2311300430107 in words is "two trillion, three hundred eleven billion, three hundred million, four hundred thirty thousand, one hundred seven".
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