Base | Representation |
---|---|
bin | 100001101000100100001… |
… | …111011011100100110011 |
3 | 22011221212111112012121111 |
4 | 201220210033123210303 |
5 | 300332020402231011 |
6 | 4525444033334151 |
7 | 325662115334020 |
oct | 41504417334463 |
9 | 8157774465544 |
10 | 2311300430131 |
11 | 811242923540 |
12 | 313b41a07357 |
13 | 139c54609114 |
14 | 7dc20748547 |
15 | 401c77c2121 |
hex | 21a243db933 |
2311300430131 has 16 divisors (see below), whose sum is σ = 2881705736448. Its totient is φ = 1800960559200.
The previous prime is 2311300430119. The next prime is 2311300430171. The reversal of 2311300430131 is 1310340031132.
It is not a de Polignac number, because 2311300430131 - 27 = 2311300430003 is a prime.
It is a super-4 number, since 4×23113004301314 (a number of 51 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (2311300430111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2317216 + ... + 3161026.
It is an arithmetic number, because the mean of its divisors is an integer number (180106608528).
Almost surely, 22311300430131 is an apocalyptic number.
2311300430131 is a deficient number, since it is larger than the sum of its proper divisors (570405306317).
2311300430131 is a wasteful number, since it uses less digits than its factorization.
2311300430131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 879402.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 2311300430131 its reverse (1310340031132), we get a palindrome (3621640461263).
The spelling of 2311300430131 in words is "two trillion, three hundred eleven billion, three hundred million, four hundred thirty thousand, one hundred thirty-one".
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