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231131112132000 = 2535389216414899
BaseRepresentation
bin110100100011011001100111…
…110101011100110110100000
31010022100220210121100122110110
4310203121213311130312200
5220243323004201211000
62135324100031131320
766453446265342543
oct6443314765346640
91108326717318413
10231131112132000
116771117724a683
1221b0a911973b40
139bc77550a9252
144110b3c49c85a
151bac3b5dc3850
hexd23667d5cda0

231131112132000 has 192 divisors, whose sum is σ = 765693229392000. Its totient is φ = 60942435276800.

The previous prime is 231131112131989. The next prime is 231131112132017. The reversal of 231131112132000 is 231211131132.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 107139450 + ... + 109275449.

It is an arithmetic number, because the mean of its divisors is an integer number (3987985569750).

Almost surely, 2231131112132000 is an apocalyptic number.

231131112132000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

231131112132000 is an abundant number, since it is smaller than the sum of its proper divisors (534562117260000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

231131112132000 is a wasteful number, since it uses less digits than its factorization.

231131112132000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 216415016 (or 216414998 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 231131112132000 its reverse (231211131132), we get a palindrome (231362323263132).

The spelling of 231131112132000 in words is "two hundred thirty-one trillion, one hundred thirty-one billion, one hundred twelve million, one hundred thirty-two thousand".