Base | Representation |
---|---|
bin | 10101100001101001… |
… | …101001010000011001 |
3 | 2012122210110100001020 |
4 | 111201221221100121 |
5 | 334313431041241 |
6 | 14341254513053 |
7 | 1445523322332 |
oct | 254151512031 |
9 | 65583410036 |
10 | 23113143321 |
11 | 9890848744 |
12 | 4590665789 |
13 | 2244655188 |
14 | 1193941289 |
15 | 90420db66 |
hex | 561a69419 |
23113143321 has 4 divisors (see below), whose sum is σ = 30817524432. Its totient is φ = 15408762212.
The previous prime is 23113143311. The next prime is 23113143337. The reversal of 23113143321 is 12334131132.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 23113143321 - 214 = 23113126937 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23113143291 and 23113143300.
It is not an unprimeable number, because it can be changed into a prime (23113143301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3852190551 + ... + 3852190556.
It is an arithmetic number, because the mean of its divisors is an integer number (7704381108).
Almost surely, 223113143321 is an apocalyptic number.
It is an amenable number.
23113143321 is a deficient number, since it is larger than the sum of its proper divisors (7704381111).
23113143321 is an equidigital number, since it uses as much as digits as its factorization.
23113143321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7704381110.
The product of its digits is 1296, while the sum is 24.
Adding to 23113143321 its reverse (12334131132), we get a palindrome (35447274453).
The spelling of 23113143321 in words is "twenty-three billion, one hundred thirteen million, one hundred forty-three thousand, three hundred twenty-one".
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