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2311323739457 is a prime number
BaseRepresentation
bin100001101000100101101…
…000010110010101000001
322011221221010101102222212
4201220211220112111001
5300332042334130312
64525450225111505
7325662520425155
oct41504550262501
98157833342885
102311323739457
11811254aa4147
12313b49788595
13139c593aa915
147dc23895065
15401c9878822
hex21a25a16541

2311323739457 has 2 divisors, whose sum is σ = 2311323739458. Its totient is φ = 2311323739456.

The previous prime is 2311323739411. The next prime is 2311323739489. The reversal of 2311323739457 is 7549373231132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1806661262641 + 504662476816 = 1344121^2 + 710396^2 .

It is a cyclic number.

It is not a de Polignac number, because 2311323739457 - 220 = 2311322690881 is a prime.

It is not a weakly prime, because it can be changed into another prime (2311323729457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1155661869728 + 1155661869729.

It is an arithmetic number, because the mean of its divisors is an integer number (1155661869729).

Almost surely, 22311323739457 is an apocalyptic number.

It is an amenable number.

2311323739457 is a deficient number, since it is larger than the sum of its proper divisors (1).

2311323739457 is an equidigital number, since it uses as much as digits as its factorization.

2311323739457 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2857680, while the sum is 50.

The spelling of 2311323739457 in words is "two trillion, three hundred eleven billion, three hundred twenty-three million, seven hundred thirty-nine thousand, four hundred fifty-seven".