Base | Representation |
---|---|
bin | 1010100000101101011100… |
… | …10111001001010111101011 |
3 | 10000211200122110102011221021 |
4 | 11100112232113021113223 |
5 | 11012200231421314201 |
6 | 121054254042353311 |
7 | 4603641021016645 |
oct | 520265627112753 |
9 | 100750573364837 |
10 | 23114144323051 |
11 | 74017209820a1 |
12 | 27138141bb837 |
13 | cb8867ac41a2 |
14 | 59ca328d9895 |
15 | 2a13ba454ea1 |
hex | 1505ae5c95eb |
23114144323051 has 2 divisors, whose sum is σ = 23114144323052. Its totient is φ = 23114144323050.
The previous prime is 23114144323031. The next prime is 23114144323091. The reversal of 23114144323051 is 15032344141132.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23114144323051 - 223 = 23114135934443 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23114144322998 and 23114144323016.
It is not a weakly prime, because it can be changed into another prime (23114144323001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11557072161525 + 11557072161526.
It is an arithmetic number, because the mean of its divisors is an integer number (11557072161526).
Almost surely, 223114144323051 is an apocalyptic number.
23114144323051 is a deficient number, since it is larger than the sum of its proper divisors (1).
23114144323051 is an equidigital number, since it uses as much as digits as its factorization.
23114144323051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34560, while the sum is 34.
Adding to 23114144323051 its reverse (15032344141132), we get a palindrome (38146488464183).
The spelling of 23114144323051 in words is "twenty-three trillion, one hundred fourteen billion, one hundred forty-four million, three hundred twenty-three thousand, fifty-one".
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