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23114144323051 is a prime number
BaseRepresentation
bin1010100000101101011100…
…10111001001010111101011
310000211200122110102011221021
411100112232113021113223
511012200231421314201
6121054254042353311
74603641021016645
oct520265627112753
9100750573364837
1023114144323051
1174017209820a1
1227138141bb837
13cb8867ac41a2
1459ca328d9895
152a13ba454ea1
hex1505ae5c95eb

23114144323051 has 2 divisors, whose sum is σ = 23114144323052. Its totient is φ = 23114144323050.

The previous prime is 23114144323031. The next prime is 23114144323091. The reversal of 23114144323051 is 15032344141132.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 23114144323051 - 223 = 23114135934443 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 23114144322998 and 23114144323016.

It is not a weakly prime, because it can be changed into another prime (23114144323001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11557072161525 + 11557072161526.

It is an arithmetic number, because the mean of its divisors is an integer number (11557072161526).

Almost surely, 223114144323051 is an apocalyptic number.

23114144323051 is a deficient number, since it is larger than the sum of its proper divisors (1).

23114144323051 is an equidigital number, since it uses as much as digits as its factorization.

23114144323051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 23114144323051 its reverse (15032344141132), we get a palindrome (38146488464183).

The spelling of 23114144323051 in words is "twenty-three trillion, one hundred fourteen billion, one hundred forty-four million, three hundred twenty-three thousand, fifty-one".