23114302041433 has 16 divisors (see below), whose sum is σ = 24523043051520. Its totient is φ = 21724789597056.

The previous prime is 23114302041353. The next prime is 23114302041461. The reversal of 23114302041433 is 33414020341132.

It is a cyclic number.

It is not a de Polignac number, because 23114302041433 - 2⁴¹ = 20915278785881 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23114302041395 and 23114302041404.

It is not an unprimeable number, because it can be changed into a prime (23114302044433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 120923691 + ... + 121114687.

It is an arithmetic number, because the mean of its divisors is an integer number (1532690190720).

Almost surely, 2^{23114302041433} is an apocalyptic number.

It is an amenable number.

23114302041433 is a deficient number, since it is larger than the sum of its proper divisors (1408741010087).

23114302041433 is a wasteful number, since it uses less digits than its factorization.

23114302041433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 241296.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 23114302041433 its reverse (33414020341132), we get a palindrome (56528322382565).

The spelling of 23114302041433 in words is "twenty-three trillion, one hundred fourteen billion, three hundred two million, forty-one thousand, four hundred thirty-three".