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2311440000000 = 2103579631
BaseRepresentation
bin100001101000101100100…
…011110110010000000000
322011222020020011002110220
4201220230203312100000
5300332312120000000
64525505541023040
7325665431553165
oct41505443662000
98158206132426
102311440000000
1181130469143a
12313b806b4a80
13139c774c5741
147dc350ba06c
15401d4b911a0
hex21a2c8f6400

2311440000000 has 352 divisors, whose sum is σ = 7701817783296. Its totient is φ = 616320000000.

The previous prime is 2311439999971. The next prime is 2311440000013. The reversal of 2311440000000 is 441132.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 239995185 + ... + 240004815.

Almost surely, 22311440000000 is an apocalyptic number.

2311440000000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2311440000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3850908891648).

2311440000000 is an abundant number, since it is smaller than the sum of its proper divisors (5390377783296).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2311440000000 is an frugal number, since it uses more digits than its factorization.

2311440000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9689 (or 9641 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 2311440000000 its reverse (441132), we get a palindrome (2311440441132).

The spelling of 2311440000000 in words is "two trillion, three hundred eleven billion, four hundred forty million", and thus it is an aban number.