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23115320324113 = 103224420585671
BaseRepresentation
bin1010100000101111101000…
…11101001111000000010001
310000211210200102021020010011
411100113310131033000101
511012210134000332423
6121055010452234521
74604012120612323
oct520276435170021
9100753612236104
1023115320324113
1174021747870a6
122713aa200ba41
13cb89c4634cc4
1459cb04b7d613
152a14387eeb0d
hex1505f474f011

23115320324113 has 4 divisors (see below), whose sum is σ = 23339740909888. Its totient is φ = 22890899738340.

The previous prime is 23115320324077. The next prime is 23115320324171. The reversal of 23115320324113 is 31142302351132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23115320324113 - 213 = 23115320315921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21115320324113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 112210292733 + ... + 112210292938.

It is an arithmetic number, because the mean of its divisors is an integer number (5834935227472).

Almost surely, 223115320324113 is an apocalyptic number.

It is an amenable number.

23115320324113 is a deficient number, since it is larger than the sum of its proper divisors (224420585775).

23115320324113 is a wasteful number, since it uses less digits than its factorization.

23115320324113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 224420585774.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 23115320324113 its reverse (31142302351132), we get a palindrome (54257622675245).

The spelling of 23115320324113 in words is "twenty-three trillion, one hundred fifteen billion, three hundred twenty million, three hundred twenty-four thousand, one hundred thirteen".

Divisors: 1 103 224420585671 23115320324113