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2311611623131 is a prime number
BaseRepresentation
bin100001101000110110110…
…010100010011011011011
322011222200012002110011011
4201220312302202123123
5300333140033420011
64525534551314351
7326002614412156
oct41506662423333
98158605073134
102311611623131
11811392552438
1231400a07b9b7
13139ca3c257a5
147dc4dbd2c9d
15401e4c92621
hex21a36ca26db

2311611623131 has 2 divisors, whose sum is σ = 2311611623132. Its totient is φ = 2311611623130.

The previous prime is 2311611623099. The next prime is 2311611623147. The reversal of 2311611623131 is 1313261161132.

2311611623131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2311611623131 - 25 = 2311611623099 is a prime.

It is a super-2 number, since 2×23116116231312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2311611623093 and 2311611623102.

It is not a weakly prime, because it can be changed into another prime (2311611621131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1155805811565 + 1155805811566.

It is an arithmetic number, because the mean of its divisors is an integer number (1155805811566).

Almost surely, 22311611623131 is an apocalyptic number.

2311611623131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2311611623131 is an equidigital number, since it uses as much as digits as its factorization.

2311611623131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3888, while the sum is 31.

Adding to 2311611623131 its reverse (1313261161132), we get a palindrome (3624872784263).

The spelling of 2311611623131 in words is "two trillion, three hundred eleven billion, six hundred eleven million, six hundred twenty-three thousand, one hundred thirty-one".