Base | Representation |
---|---|
bin | 100001101001010101101… |
… | …100010111101100001001 |
3 | 22012001000022200210200022 |
4 | 201221111230113230021 |
5 | 300340220301144402 |
6 | 4530102232150225 |
7 | 326021511402365 |
oct | 41512554275411 |
9 | 8161008623608 |
10 | 2312130099977 |
11 | 8116291897a5 |
12 | 314133838375 |
13 | 13a057479919 |
14 | 7dc9c9d82a5 |
15 | 4022555a2a2 |
hex | 21a55b17b09 |
2312130099977 has 2 divisors, whose sum is σ = 2312130099978. Its totient is φ = 2312130099976.
The previous prime is 2312130099971. The next prime is 2312130100073. The reversal of 2312130099977 is 7799900312132.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1957603932736 + 354526167241 = 1399144^2 + 595421^2 .
It is a cyclic number.
It is not a de Polignac number, because 2312130099977 - 26 = 2312130099913 is a prime.
It is not a weakly prime, because it can be changed into another prime (2312130099971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1156065049988 + 1156065049989.
It is an arithmetic number, because the mean of its divisors is an integer number (1156065049989).
Almost surely, 22312130099977 is an apocalyptic number.
It is an amenable number.
2312130099977 is a deficient number, since it is larger than the sum of its proper divisors (1).
2312130099977 is an equidigital number, since it uses as much as digits as its factorization.
2312130099977 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1285956, while the sum is 53.
The spelling of 2312130099977 in words is "two trillion, three hundred twelve billion, one hundred thirty million, ninety-nine thousand, nine hundred seventy-seven".
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